VTA Mk3 Octal Driver board mod to use 7193?

I was reading about the 7193: a single triode with G and A out to a top electrode for better HF characteristics (HF in the sense of RF). but some are saying its a great sounding audio tube. Since the VTA Octal driver board "wastes" a triode in the gain stage 6SN7, I was thinking modifying the board to use a 7193 might be a good idea: you'd not waste that 6SN7 triode and you'd get a better sounding result assuming the people who have switched to 7193's from 6SN7's in other amps they own are correct in that its a better sounding tube.

I might get my hands on a couple and some tube electrode caps and try this out. the 7193 is electronically equivalent to the 6SN7 so it would just be a matter of rewiring the socket a bit. and since the VTA design does not use the other triode this seems like an easy upgrade.

Thoughts?

I ordered some NOS 7193's and some electrode caps. I'll make the mods and let you know how it sounds. it will take a few weeks to get everything together. should be a fun project and from what I have read the 7193's sound a lot better than 6SN7's

Thanks For your info on the MK3s,in this post an others. I well ck on cost from my tube guy on the $$ of the 7193.I have been useing the 6SN7 for driver in tube amps for years vary hard to beat the sound.well to me.goodluck

Thanks for the site Bob

I bought a few 7193's on ebay NOS US Navy 1943 for about $9 per tube including shipping. so they are pretty cost effective. I'll have to run a top electrode for both G and P but that won't be a problem. and of course mod the circuit board to work with the 7193. i'll post how it works out.

Any progress on this project?
I've had this thought previously as the tubes are CHEAP! And,as you've mentioned,supposedly sound great.
Regards,
Dan

cheap tubes? for $9? there are dozens of 6SN7s on ebay for around a $1 each, even nice quads for $6, of course, all slightly used, but
I'll take those over a new production tube any day. Anyone tried the russian 6H8C which runs $3-4 each?